Ñáîðíèê ðåôåðàòîâ

Êóðñîâàÿ ðàáîòà: Ðîçðàõóíîê ô³íàíñîâèõ ïîêàçíèê³â òà åêîíîì³÷íî¿ åôåêòèâíîñò³ ïåðåâåçåíü

Êóðñîâàÿ ðàáîòà: Ðîçðàõóíîê ô³íàíñîâèõ ïîêàçíèê³â òà åêîíîì³÷íî¿ åôåêòèâíîñò³ ïåðåâåçåíü

̲ͲÑÒÅÐÑÒÂÎ ÍÀÓÊÈ ÒÀ ÎѲÒÈ ÓÊÐÀ¯ÍÈ

ÃÎÐ˲ÂÑÜÊÈÉ ÒÅÕͲÊÓÌ ÄÎÍÅÖÜÊÎÃÎ

ÍÀÖ²ÎÍÀËÜÍÎÃÎ ÒÅÕͲ×ÍÎÃÎ ÓͲÂÅÐÑÈÒÅÒÓ

ÊÓÐÑÎÂÀ ÐÎÁÎÒÀ

ÎÏÏ.ÊÐ.01.0.00.00.ÏÇ

ÃÐÓÏÀ Å301

Áåðåçí³êåð Ìèêèòà Ìèõàéëîâè÷


2003 ð.


 

 

 

 

Ðîçðàõóíîê ô³íàíñîâèõ ïîêàçíèê³â

òà åêîíîì³÷íî¿ åôåêòèâíîñò³

ïåðåâåçåíü

 

 

Ïîÿñíþâàëüíà çàïèñêà

ÎÏÏ ÊР  00.00.00.ÏÇ

 

 

 

 

 

 

 

 

Êåð³âíèê ïðîåêòó

       ×óáîâñüêà Í.À.

Ðîçðîáèâ ñòóäåíò
 

     Áåðåçí³êåð Ì.Ì.

2003 ð.


̲ͲÑÒÅÐÑÒÂÎ ÍÀÓÊÈ ÒÀ ÎѲÒÈ ÓÊÐÀ¯ÍÈ

ÃÎÐ˲ÂÑÜÊÈÉ ÒÅÕͲÊÓÌ ÄÎÍÅÖÜÊÎÃÎ

ÍÀÖ²ÎÍÀËÜÍÎÃÎ ÒÅÕͲ×ÍÎÃÎ ÓͲÂÅÐÑÈÒÅÒÓ

 

ÇÀÂÄÀÍÍß

ÍÀ ÊÓÐÑÎÂÅ ÏÐÎÅÊÒÓÂÀÍÍß ÏÎ ÏÐÅÄÌÅÒÓ

“ÅÊÎÍÎ̲ÊÀ, ÎÐÃÀͲÇÀÖ²ß ÒÀ ÏËÀÍÓÂÀÍÍß ÀÂÒÎÌÎÁ²ËÜÍÎÃÎ ÒÐÀÍÑÏÎÐÒÓ”

Ñòóäåíòà ãðóïè Å402_____


Íà çàâäàííÿ: ___________   

 

²ñõîäíà ³íôîðìàö³ÿ.

ÏÎÊÀÇÍÈÊÈ

ÓÌ.ÏÎÇÍ.

ÇÍÀ×ÅÍÍß.

Ìàðêà ðóõîìîãî ñêëàäó.

Êàìàç -5320

ʳëüê³ñòü àâòîìîá³ë³â.

À³

12

Ãîäèíè ïðàö³, ãîä.

Òí

12,3

Êîåô³ö³åíòè âèêîíàííÿ:

Âàíòàæîì³ñòêîñò³

Ïðîá³ãó

Ïàðêó

g 1

25

Lâ.ã

21

1 .ÂÈÐÎÁÍÈ×À ÏÐÎÃÐÀÌÀ Ç ÅÊÑÏËÓÀÒÀÖ²¯

ÐÓÕÎÌÎÃÎ ÑÊËÀÄÓ ÂÀÍÒÀÆÍÎÃÎ ÏÀÐÊÓ

Òàáëèöÿ 1.1. Òåõí³÷íà õàðàêòåðèñòèêà àâòîìîá³ëÿ
Íàéìåíóâàííÿ ïîêàçíèêà   Çíà÷åííÿ
1. Çàâîä âèãîòîâëþâà÷ Êàìñêèé àâò. Çàâîä
 2. Âàíòàæîï³äéîìí³ñòü 8
 3.  Ðîçì³ð àâòîìîá³ëþ(ãàáàðèòè)
äëèíà 7435
øèðèíà 2500
âûñîòà 2530
 4. Ðîçì³ð øèí 260R-508
5. Ìàðêà ïàëèâà ÄÒ
 6.  Òèï äâèãóíà ÊàìÀÇ-740Ä
 7. Ïîòóæí³ñòü äâèãóíà 210 ë.ñ.

1.1.    Ðîçðàõóíîê ïîêàçíèê³â ðîáîòè àâòîìîá³ëÿ çà äåíü.                   

                                  

1.1.1. ʳëüê³ñòü ¿çäîê.                                 

                                                           7(¿çä)  

äå:                              

Òí - ÷àñ â íàðÿä³                               

β - êîåô³ö³ºíò âèêîðèñòàííÿ ïðîá³ãó                               

Vò- øâèäê³ñòü òåõí³÷íà                              

l â¿ - äîâæèíà âàíòàæíî¿ ¿çäêè                               

t í-ð - ÷àñ íàâàíòàæåííÿ-ðîçâàíòàæåííÿ                           

                                  

           

1.1.2. Îáñÿã ïåðåâåçåíü ó òîííàõ

                                  

Qäåí=qí*γ*Z¿=56,00(ò)

äå:

γ - êîåô³ö³ºíò âèêîðèñòàííÿ âàíòàæîï³äéîìíîñò³

                       

1.1.3. Îáñÿã ïåðåâåçåíü ó òîíî-ê³ëîìåòðàõ:

                                  

Ðäåí=Qäåí*γ*Z¿=1176,00(ò.êì)

                       

1.1.4. Äîáîâèé ïðîá³ã

                                  

Läîá=  lâ¿*Z¿  =229,7(êì)                   

                 β                           

1.1.5. Íàâàíòàæåíèé ïðîá³ã çà äåíü

                                  

Lâ=Läîá*β =    147(êì)

                       

1.2. Âèðîáíè÷à ïðîãðàìà ïàðêó ðóõîìîãî ñêëàäó

1.2.1. Àâòîìîá³ëå äí³ â ãîñïîäàðñòâ³ çà ð³ê

                                  

ÀÄã=À³*Äê=   4380(àâòî-äí³)                      

äå:                              

À³ - îáë³êîâà ê³ëüê³ñòü àâòîìîá³ë³â                                  

                                  

1.2.2. Àâòîìîá³ëå äí³ â åêñïëóàòàö³¿

                                  

ÀÄð=ÀÄã*αâ=3175,5(àâòî-äí³)       

           

1.2.3. Îáñÿã ïåðåâåçåíü ó òîíàõ çà ð³ê

                                  

Qp=Qäåí*Àäð=177828(ò)

                       

1.2.4. Îáñÿã ïåðåâåçåíü ó òîíî-ê³ëîìåòðàõ çà ð³ê

                       

Pp = Ðäåí * ÀÄð=         3734388(ò.êì)

                       

1.2.5. Çàãàëüíèé ïðîá³ã çà ð³ê

                                  

Lçàã = Läîá * ÀÄð=      729412,35(êì)

                       

1.2.6. Íàâàíòàæåíèé ïðîá³ã çà ð³ê

                       

Lâ.ð = Lâ * ÀÄð=466798,5(êì)

                       

1.2.7. г÷íà ê³ëüê³ñòü ¿çäîê

                                  

Z¿ð = Z¿* ÀÄð=22229(¿çä)

                       

1.2.8. Àâòîìîá³ëå ãîäèíè â åêñïëóàòàö³¿ çà ð³ê              

                                  

ÀÃåð=  Òí*ÀÄð=39058,7(àâòî-ã)

                       

1.2.9. Àâòîìîá³ëå ãîäèíè ïðîñòîþ ï³ä íàâàíòàæåííÿì-ðîçâàíòàæåííÿì çà ð³ê

                       

ÀÃïð.ð=tí-ð*ÀÄð* Z¿=10447,4(àâòî-ã)

                       

1.2.10. Àâòîìîá³ëå ãîäèíè ó ðóñ³ çà ð³ê

                       

ÀÃðóõ.ð= Àãåð- ÀÃïð.ð=28611,3(àâòî-ã)


2. ÂÈÐÎÁÍÈ×À ÏÐÎÃÐÀÌÀ Ç ÒÅÕͲ×ÍÎÃÎ ÎÁÑËÓÃÎÂÓÂÀÍÍß ² ÐÅÌÎÍÒÓ ÐÓÕÎÌÎÃΠ    ÑÊËÀÄÓ

Òàáëèöÿ 2.1. Íîðìàòèâí³ äàí³

Íàéìåíóâàííÿ çíà÷åíü

Óìîâí³ ïîçíà÷êè

Ïîêàçíèêè

1. Ïðîá³ã àâòîìîá³ëÿ äî
êàï³òàëüíîãî ðåìîíòó

Lêð

300000
2. Ïðîá³ã äî ïåðøîãî òåõí³÷íîãî
 îáñëóãîâóâàííÿ

Lòî-1

4000
3. Ïðîá³ã äî äðóãîãî òåõí³÷íîãî
îáñëóãîâóâàííÿ

Lòî-2

12000
4. Òðóäîì³ñòê³ñòü ïåðøîãî
òåõí³÷íîãî îáñëóãîâóâàííÿ

tòî-1

1,91
5. Òðóäîì³ñòê³ñòü äðóãîãî
òåõí³÷íîãî îáñëóãîâóâàííÿ

tòî-2

8,63
6. Òðóäîì³ñòê³ñòü ùîäåííîãî
îáñëóãîâóâàííÿ

tùî

0,75
7. Òðóäîì³ñòê³ñòü ïîòî÷íîãî
ðåìîíòó

tïð

6,7

                                                                                                                     

2.1.  Ðîçðàõóíîê ê³ëüêîñò³ âïëèâ³â

                                              

2.1.1. ʳëüê³ñòü êàï³òàëüíèõ ðåìîíò³â

                                              

Nêð =  Lçàã  =2

            Lêð

2.1.2. ʳëüê³ñòü ÒÎ-2

                                              

Nòî-2     =  Lçàã  - -  Nêð = 59

                Lòî-2

2.1.3. ʳëüê³ñòü TO-I

                                  

Nòî-1 =   Lçàã  - -  (Nêð+Nòî-2) = 121

                Lòî-2                                

2.1.4. ʳëüê³ñòü ÙΠ

                                  

Nùî = Lçàã        =3176

            Läîá

2.2.    Òðóäîì³ñòê³ñòü îáñëóãîâóâàíü                                          

2.2.1. Òðóäîì³ñòê³ñòü ÙΠ  

                                  

Òùî = Nùî*tùî = 2382 (÷îë-ã)

2.2.2. Òðóäîì³ñòê³ñòü TO-I  

                                  

Òòî-1 = tòî-1*Nòî-1 = 231,1 (÷îë-ã)

2.2.3. Òðóäîì³ñòê³ñòü ÒÎ-2 

                                  

Òòî-2     =  tòî-2*Nòî-2 =509,2(÷îë-ã)

2.2.4. Òðóäîì³ñòê³ñòü ÏÐ

                                              

Òïð = tïð*Lçàã/1000 = 4887,1(÷îë-ã)

2.2.5. Çàãàëüíà òðóäîì³ñòê³ñòü

                                              

Òçàã = Òùî+Òòî-1+Òòî-2 +Òïð = 8009,4 (÷îë-ã)  


3.×ÈÑÅËÜͲÑÒÜ ÏÅÐÑÎÍÀËÓ                                      

                                                                      

3.1. ×èñåëüí³ñòü âî䳿⠠                                                                

Nâ =   1,05*ÀÃå =23(÷îë.)  

           ÔÐ×*Êïò                                                                   

äå:

1,05   - êîåô³ö³ºíò, ùî âðàõîâóº ï³äãîòîâ÷î-çàêëþ÷íèé ÷àñ;                                                  

Êïò- êîåô³ö³ºíò, ùî âðàõîâóº ïðîäóêòèâí³ñòü ïðàö³, ( Êïò = 1.05)

ÔÐ×1â - ôîíä ðîáî÷îãî ÷àñó,ãîä                                                             

ÔÐ×1â = (Äê - Äâ³äï - Äñâ – Ääåðæ.îáîâ - Äõâîð - Äâèõ) * Òð.ä- Äïñ * t1=1695 (ã)                                  

äå:                                                                 

Äâ³äï -      äí³ â³äïóñòêè [ùîð³÷íà äîäàòêîâà â³äïóñòêà âñòàíîâëåíà òðèâàë³ñòþ 24 êàëåíäàðíèõ äí³ äëÿ âñ³õ ïðàöþþ÷èõ ÀÒÏ,                                                              

äëÿ âî䳿â âñòàíîâëþºòüñÿ ùå äîäàòêîâà ùîð³÷íà â³äïóñòêà çà îñîáëèâèé õàðàêòåð ðîáîòè,ÿêà âñòàíîâëåíà â³ä 4 äî 7 êàëåíäàðíèõ äí³â (çã³äíî óìîâ,âèçíà÷íèõ ó Êîëåêòèâíîìó äîãîâîð³ ÀÒÏ)                                                                  

Äñâ                - äí³ ñâÿòêîâ³ ïåâíîãî ðîêó;                                                            

Ääåðæ.îáîâ  - äí³ íåÿâêè íà ðîáîòó â çâ'ÿçêó ç âèêîíàííÿì äåðæàâíèõ îáîâ'ÿçê³â, (3äí)

Äõâîð            - äí³ íåÿâêè íà ðîáîòó ç ÷è õâîðîáè ³íøèõ ïîâàæíèõ ïðè÷èí, Äõâîð = 5 äí.; 

Äâèõ              - äí³ âèõ³äí³ ïåâíîãî ðîêó;                                                              

Tp ä                - íîðìàòèâíà òðèâàë³ñòü ðîáî÷îãî äíÿ,ãîä (8 ãîä.)                         

t1                    - ÷àñ çì³íè íà ÿêèé ñêîðî÷åíèé ðîáî÷èé äåíü ó ñâÿòêîâ³ äí³, ti = 1 ì;            

Äïñ                 - äí³ ïåðåäñâÿòêîâ³ ïåâíîãî ðîêó.                                                             

3.2. ×èñåëüí³ñòü ðåìîíòíèê³â                                                                 

Nð.ð.=         Tçàã            =  4(÷îë)

                ÔÐ×ð*Êïò

           

ÔÐ×ð=  (Äê – Äâ³äï.ð - Äñâ – Ääåðæ.îáîâ - Äõâîð - Äâèõ) * Òð.ä- Äïñ * t1=1743

           

3.3. ×èñåëüí³ñòü äîïîì³æíèõ ðîá³òíèê³â                                                          

Νäîï. = 0,2 * Νρ.ρ. = 1 (÷îë),                                                             

äå:                                                                 

0,2 - 20% â³ä ÷èñåëüíîñò³ ðåìîíòíèê³â                                                                                      

3.4. ×èñåëüí³ñòü êåð³âíèê³â ³ ñïåö³àë³ñò³â:                                                                     

Nêep = (Nâ + Näîï +Νρ,ρ.) * 0,1 = 3 (÷îë)                                                                 

                                                                      

äå:                                                                 

0,1 - 10% â³ä ñóìè ê³ëüêîñò³ âî䳿â, ðåìîíòíèê ³ äîïîì³æíèõ                                                             

ðîá³òíèê³â                                                               

3.5. ×èñåëüí³ñòü ïåðñîíàëó ÀÒÏ                                                 

                                                          

Nïep = Nâ+ Np.p + Νκ+Näîï + Nêep =31 (÷îë)                                               


4.ÂÈÒÐÀÒÈ ÍÀ ÎÏËÀÒÓ ÏÐÀÖ²                                                                     

                                                                                                                                

4.1.Îñíîâíà çàðîá³òíà ïëàòà âî䳿â, ùî ïðàöþþòü â³äðÿäíî.                                                                                                                              

                                                                                                                                

4.1.1. ³äðÿäíà çàðîá³òíà ïëàòà âî䳿â âàíòàæíèõ àâòîìîá³ë³â:           

ÎÔÇÏ â = (Qp * Ñò + Pp * Cò.êì) * Êâ + ÀÃï-ç * Ñãîä = 74544,4 (ãðí.)

äå:

Ñãîä      - òàðèôíà ãîäèííà ñòàâêà âîä³ÿ III êëàñó (1,684ãðí)                                                    

Êâ         - êîåô³ö³ºíò, ùî âðàõîâóº êëàñ âàíòàæó (1,0)

ÀÃï-ç    - àâòîìîá³ë³ ãîäèíè ï³äãîòîâ÷î-çàêëþ÷í³,                                                                     

Ñò.êì            - â³äðÿäíà ðîçö³íêà çà 1 òîíî-ê³ëîìåòð.

                                                                      

ÀÃï-ç = 0,05 * ÀÃå = 1952,9  (àâòî-ã),

                                                                                             

äå:                                                                                                                                                   

0,05    - 5% â³ä àâòîìîá³ëå ãîäèí â åêñïëóàòàö³¿;                                               

Ñò      - â³äðÿäíà ðîçö³íêà çà îäíó òîíó ïåðåâåçåíîãî âàíòàæó;

                                  

Cò =  Ñãîä * Í÷àñò /60 = 0,0017   (ãðí)

Ñò.êì     =Ñãîä*Í÷àñ.ò.êì  =  0,019 (ãðí)

äå:     Í÷àñ.ò       - íîðìà ÷àñó çà òîíó ïåðåâåçåíîãî âàíòàæó;

          Íâð.ò.êì   - íîðìà ÷àñó çà 1òîíî-ê³ëîìåòð;     

Í÷àñ.ò  =     tí-ð    =  0,06 (ð³ê)                                                                                                                                 qí* γ

                                   1

Íâð.ò.êì  =                                     =  0,011

                      Vòð* βð*qí* γ

4.2. Äîäàòêîâà çàðîá³òíà ïëàòà

4.2. 1 . Íàäáàâêà çà êëàñí³ñòü :                                                                             

                                                                                 

Hêë = Ñãîä * ÔÐ×1â (0,25*Νâ² + 0,1 * Nâ²²) = 7564,1 (ãðí)                                                                           

äå:   Νâ² , Nâ²²  - ÷èñåëüí³ñòü âî䳿â â³äïîâ³äíî ² ³ II êëàñ³â;                                                                                                                                     

0,25 - 25% - äîïëàòà âîä³ÿì ² êëàñó;                                                                    

0, 1 - 1 0% - äîïëàòà âîä³ÿì II êëàñó;                                                                  

                                                                      

Νâ² = Nâ *ಠ  = 7 (÷îë.)                                                                

Νâ²² =            Nâ *ಲ = 9 (÷îë.)

           

à³, àö - â³äñîòîê âî䳿â â³äïîâ³äíî ² ³ II êëàñ³â,                                                              

à²=30%,ಲ=40%

4.2.2. Ïðåì³ÿ âîä³ÿì âàíòàæíèõ àâòîìîá³ë³â çà ñâîº÷àñíå ³ ÿê³ñíå âèêîíàííÿ çàâäàíü:                                                                                                                            

Ï = àïð * ÎÔÇÏ â /100 = 22363,3 (ãðí.)

äå:      

àïð - â³äñîòîê ïðå쳿 30%

4.3. Äîïëàòà çà êåð³âíèöòâî áðèãàäîþ

Äáð = ÔÐ× * Ñãîä * Ν6ρ * Êáð = 1712,6 (ãðí)                                                         

äå:                                                     

Ν6ρ - ê³ëüê³ñòü áðèãàä;                                                      

                                                          

Ν6ρ =   Nâ   =  3

            náð

                                              

náð=8                                                                                                            

äå:                                                                                                                

náð - ê³ëüê³ñòü ëþäèí ó áðèãàä³,                                                                                                   

Êáð-êîåô³ö³ºíò,âðàõîâóþ÷èé äîïëàòó çà êåð³âíèöòâî áðèãàäîþ â çàëåæíîñò³ â³ä ÷èñåëüíîñò³ âî䳿â ó áðèãàä³ (0,2)

4.4. Äîïëàòà çà ðîáîòó ó âå÷³ðí³é òà í³÷íèé ÷àñ                                                            

                                                                      

Äâ-í. = Ñãîä*(0,2 * ÀÃâ + 0,4 * ÀÃí)= 8556,1  (ãðí)                                                           

äå:                                                                                                                            

ÀÃâ, ÀÃí - àâòîìîá³ëå ãîäèíè ðîáîòè â³äïîâ³äíî ó âå÷³ðí³é ³   í³÷íèé ÷àñ                                       

ÀÃÂ= tâ * ÀÄð= 12702 (àâòî-ã)                                                                 

                                                                      

ÀÃÍ = tí * ÀÄð= 6351 (àâòî-ã)                                                                                         

äå:                                                                                                                                       

tâ,tí    - ê³ëüê³ñòü ãîäèí, â³äïðàöüîâàíèõ â³äïîâ³äíî ó    âå÷³ðí³é ³ í³÷íèé ÷àñ,         

tâ = 4  

tí = 2  

0,2    - 20% - â³äñîòîê äîïëàòè çà ðîáîòó ó âå÷³ðí³é ÷àñ,                                                                      

0,4    - 40% - â³äñîòîê äîïëàòè çà ðîáîòè â í³÷íèé ÷àñ.                                                            

                                                                      

4.2.6. Äîïëàòà çà åêñïåäóâàííÿ âàíòàæó                                                            

                                                                      

Äåêñ =aåêñ * ÇÏïîã = 6906,4 (ãðí)                                                                                                                                        

äå:àåêñ - â³äñîòîê çà åêñïåäèðóâàííÿ âàíòàæó â³ä ïîãîäèííî¿ çàðîá³òíî¿ ïëàòè:                                                                   

-äëÿ âàíòàæ³â,ÿê³ íå ïîòðåáóþòü áàãàòî ÷àñó íà ïðèéìàííÿ, çäà÷ó ³ îôîðìëåííÿ äîêóìåíò³â- 10%;                                                                                                                              

ÇÏïîã - ïîãîäèííà çàðîá³òíà ïëàòà.

                                                                      

ÇÏïîã = 1,05 * AÃe * Ñãîä = 69063,6 (ãðí)                                                          


4.2.7. Äîïëàòà çà ó÷àñòü ó íàâàíòàæíî-ðîçâàíòàæóâàëüíèõ ðîáîòàõ                                                 

                                                          

Äí-ð = àí-ð * ÇÏòàð=10359,5 (ãðí)                                                     

äå:                                                                                                                

àí-ð - â³äñîòîê äîïëàòè çà ó÷àñòü ó íàâàíòàæíî-   ðîçâàíòàæóâàëüíèõ ðîáîòàõ(15%)

4.2.9. Ñóìà íàäáàâîê ,äîïëàò ³ ïðåì³é:                                                               

                                                                      

ΣÍÄÏ=Íêë+Äáð+Äåêñ+Äñâ+Äí-ð+Ï+Äâí=57462 (ãðí)                                                        

                                                                      

4.2. ²Î.Ãàðàíò³éí³ òà êîìïåíñàö³éí³ âèïëàòè:

                                                                      

ÃÊÂ=(ÎÔÇÏ â +Σ ÍÄÏ)*Ïãêâ/100 = 14784,7 (ãðí)

                                                                      

äå: Ïãêâ-â³äñîòîê ãàðàíò³éíèõ òà êîìïåíñàö³éíèõ âèïëàò;                                                                  

Ïãêâ= (Äâ³ä/Äê-Äñâ-Äâèõ-Äâ³ä)* ² 00+1 , 1 =11,2%

äå:Äâ³ä-òðèâàë³ñòü â³äïóñòêè ó ðîáî÷èõ äíÿõ äëÿ âî䳿â:                                                          

â³ä Ç,0ò ³ âèùå-23 äí³

Äâèõ-ê³ëüê³ñòü âèõ³äíèõ äí³â çà ïåâíèé ð³ê.(104)                                                        

4.2. 1 1 Ôîíä äîäàòêîâî¿ çàðîá³òíî¿ ïëàòè:

                                                                      

ÄÔÇÏâ = ÃÊÂ+ ΣÍÄÏ = 72246,7 (ãðí)                                                               

                                                                      

4.3.3àãàëüíèé ôîíä çàðîá³òíî¿ ïëàòè âî䳿â:

                                                                      

ÇÔÇÏâ=ÎÔÇÏâ+ÄÔÇÏâ = 146791,1 (ãðí)

4.4. Ñåðåäíüîì³ñÿ÷íà çàðîá³òíà ïëàòà âî䳿⠠                                                               

                                                                      

ÇÏñåð.ì =  ÇÔÇÏâ  = 531,9 (ãðí.)                                                                 

                   Nâ*nìic                                                               

                                                                      

äå:     nì³ñ.- ê³ëüê³ñòü ì³ñÿö³â ó ðîö³, nì³ñ =12

4.5.Âèïëàòè ç ôîíäó ìàòåð³àëüíîãî çàîõî÷óâàííÿ:                                                                  

                                                                      

Âìç=àìç*ÇÔÇÏâ/100=29358,2 (ãðí)                                                            

                                                                      

äå: àìç-ðîçì³ð âèïëàò ç ôîíäó ìàòåð³àëüíîãî çàîõî÷óâàííÿ(20%)                                                                                                                            

4.6. Çàãàëüíèé ôîíä çàðîá³òíî¿ ïëàòè âî䳿â ç óðàõóâàííÿì âèïëàò ç ôîíäó ìàòåð³àëüíîãî çàîõî÷óâàííÿ:                                                                      

                                                                      

ÇÔÇÏìç= ÇÔÇÏâ+Âìç=176149,3 (ãðí)

4.7.³äðàõóâàííÿ ç ôîíäó îïëàòè ïðàö³ âî䳿â:

                                                                      

4.7.1. Ó ïåíñ³éíèé ôîíä                                                               

                                                                      

Bï.ô. =ÇÔÇÏìç* àïô=56367,8 (ãðí)                                                             

äå: àïô - ðîçì³ð â³äðàõóâàíü ó ïåíñ³éíèé ôîíä, àïô = 32%,                                                                 

4.7.2 Â ôîíä çàéíÿòîñò³                                                                 

                                                                      

Âô.ç. = ÇÔÇÏìç* àôç = 3699,1 (ãðí)                                                             

äå: àôç - ðîçì³ð â³äðàõóâàíü ó ôîíä çàéíÿòîñò³, àôç - 2,1%                                                                    

                                                                      

4.7.3. Ó ôîíä ñîö³àëüíîãî ñòðàõóâàííÿ                                                              

                                                                      

Âñ.ñ= ÇÔÇÏìç* Çñ.ñ = 5108,3 (ãðí)                                                                                                                                      

Ñòðàíèöû: 1, 2


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